Partition coefficientK = [Butanedioic acid]Ethoxyethane ÷ [Butanedioic acid]Water
K = 5 means that, at equilibrium, the concentration in Ethoxyethane is 5 times the concentration in Water.
ONE EXTRACTION
10 cm³ Ethoxyethane
Mass extracted1.667 g
3.333 g remains in Water
compared with
5 EQUAL EXTRACTIONS
5 × 2 cm³ Ethoxyethane
Total mass extracted1.895 g
3.105 g remains in Water
Additional solute recovered by splitting the solvent0.229 g37.9% of the original solute extracted
Same total Ethoxyethane volume, divided into more extractions